1221. Split a String in Balanced Strings - LeetCode Solution

class Solution:
    def balancedStringSplit(self, s: str) -> int:
        count = -1
        stack = []
        
        for i in range(len(s)):
            if not stack:
                count+=1
                stack.append(s[i])
            else:
                if stack[-1] != s[i]:
                    stack.pop()
                else:
                    stack.append(s[i])
        if not stack:
            count+=1
        return count